We have $\displaystyle u(1-y,y)=sin \pi t$ for any real y so 1-y=x

Now we change variables to a=x+y and b=6x+y.

After substitution we obtain u(0,b)=f(b).

Find f(b).

Thx for any help.

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- Jan 27th 2011, 02:10 AMslavertChange of variables
We have $\displaystyle u(1-y,y)=sin \pi t$ for any real y so 1-y=x

Now we change variables to a=x+y and b=6x+y.

After substitution we obtain u(0,b)=f(b).

Find f(b).

Thx for any help.