i have got this information on a assigment:
f (x) = ln 2x , g(x) = cos(x - p / 2) , a (x) = 2x+ | x - 2 | ,
and the question is to draw the curve of y = f (|1- x |)
i think it will then be y = f (|1-ln2x|) right ?
If you're familiar with ln(x) you could also do it this way.
Has a vertical asymptote at x=0 and f(x) = 0 at x = 1.
makes the function even and symmetric about the y-axis.
Reflect the graph about the y-axis.
Shift the graph 1 unit to the right.
Shift the graph up ln2 units.