I am doing some circular edging in my garden and want to determine how many bricks I would need (at least get close).
The brick edge is 76mm, the radius of the curve is 5,500mm. After rifling through my Uni text books I felt that using part of the method of exhaustion might give me the answer.
The equation is l = 2rsin(pi/n) where l = 76, r =5500 and n = no. of bricks (I hope that this is correct.)
Plugging in and simplying I get 6.91^10-3 = sin (pi/n).
Question: How do I rearrange to solve for n?
I have looked at this for a long time but Uni was such a long, long time ago.
int the equation , the expression would be a very small number in gardening. I wouldn't imagine your garden requires less than say 15 to 20 bricks. When x is very small, y= sin(x) can be very well approximated by y = x. so your equation can be well approximated simply by which basicly gives awkard's estimation anyway