Hi, im new here. Just wondering if someone could walk me through solving this for equation for V2. I have a solution but some parts seemed to have been skipped and i dont quite understand why:

150*V2^1.3 = 100*((5*10^-3)+V2)^1.3

Thanks

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- Jan 13th 2011, 03:31 AMkenmungerRe-arranging formula
Hi, im new here. Just wondering if someone could walk me through solving this for equation for V2. I have a solution but some parts seemed to have been skipped and i dont quite understand why:

150*V2^1.3 = 100*((5*10^-3)+V2)^1.3

Thanks - Jan 13th 2011, 03:38 AMe^(i*pi)

Take the log of both sides (I shall use natural log)

You can then use the laws of logs to separate what's inside

Chances are there is an easier way than using logs but there is more than one way to skin a mathematical cat :) - Jan 13th 2011, 03:41 AMProve It

Can you go from here? - Jan 13th 2011, 03:45 AMkenmunger
I thought i could but im not getting the same answer as my solution.

Logs were never my strong point... - Jan 13th 2011, 03:47 AMProve It
You don't need logarithms, see my post above...

- Jan 13th 2011, 04:02 AMkenmunger
Yeah, i just worked through it compared to the given solution. It has been done the same way as you "pove it" only difference is your (3^10/13)/(2^10/13) is written as (150/100)^1/1.3. Thanks for the help both of you, i can make sense of it now :)

- Jan 13th 2011, 04:11 AMkenmunger
I tell a lie... I'm not 100% sure why the +1 gets rid of the V2?!?

- Jan 13th 2011, 05:06 AMDrSteve
Prove it split the fraction into two pieces. More precisely he used the following:

.

Do you see it now? - Jan 13th 2011, 06:27 AMkenmunger
I do... spot on that, cheers :)