FOIL of square root

**nando29** · January 11th 2011, 10:05 PM

The problem is:

(sqrt(x-5)-sqrt(5))/(x-10)x(sqrt(x-5)+sqrt5)/(sqrt(x-5)+sqrt5)

This link shows exactly what the equation looks like
(sqrt(x-5)-sqrt(5))/(x-10) (sqrt(x-5)+sqrt5)/(sqrt(x-5)+sqrt5 - Wolfram|Alpha)

The complete steps for FOIL on the numerator is what i'm stuck on. I know the numerator will be (x-5)-5 after the numerator is solved and thereon i know what to do.

thanks

**Prove It** · January 11th 2011, 10:08 PM

The numerator is a difference of two squares: $\displaystyle (a - b)(a + b) = a^2 - b^2$ .

Thread: FOIL of square root