Which is the radius of the circle x2 + y2 — 2(x + 3y) = 26
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$\displaystyle \begin{array}{l} x^2 + y^2 - 2\left( {x + 3y} \right) = 26 \\ \left( {x^2 - 2x} \right) + \left( {y^2 - 6y} \right) = 26 \\ \left( {x - 1} \right)^2 + \left( {y - 3} \right)^2 = 36 \\ \end{array}$ Can you finish?
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