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Math Help - lg equation

  1. #1
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    lg equation

    does someone know how to salve this ?

    x^(1+lg(x))=(10x)^-2
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  2. #2
    Master Of Puppets
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    Using guess and check on powers of 10 you'll find x = 1/10 will do the job.
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  3. #3
    MHF Contributor Also sprach Zarathustra's Avatar
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    Quote Originally Posted by paulaa View Post
    does someone know how to salve this ?

    x^(1+lg(x))=(10x)^-2
    x^{(1+log(x))}=(10x)^{-2}

    logx^{(1+log(x))}=log(10x)^{-2}

    logx(1+logx)=-2(1+logx)

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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by Also sprach Zarathustra View Post
    x^{(1+log(x))}=(10x)^{-2}

    logx^{(1+log(x))}=log(10x)^{-2}

    logx(1+logx)=-2(1+logx)

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    \text{lg} is ambiguous it can denote a base 10 or base 2 logarithm

    CB
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