a line with y-intercept 5 and positive slope is drawn such that this line intersect x^2+y^2 = 9. What is the least slope of such a line?
my solution:
the line through A (0,5) has at least slope, when it is tangent to the circle at B.
Let B= <AOB. Since < ABO = 90, then OB = 3, OA = 5, AB = 4
hence tanB = 3/4.
therefore, the minimum slope of that line is 3/4....
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