I get
Finish it.
Proving identities of any sort has never been my strongpoint. No, this is not trig identities. I have attempted to figure out this problem multiple times with rearranging and such and I have yet to be able to prove it. The answers do not show any steps or anything, it just says: True. The question looks like:
[3^(2n) 27^(5n+1) 9^(6n)] / 81^(4n-7) = [ 9^(7n) 3^(8n+28)] / 27^(3n-1)
If anyone could explain to me their process of solving this I would be grateful.