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Thread: Limits of indeterminant form.

  1. January 9th 2011, 01:38 PM #1
    niazk90
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    Limits of indeterminant form.

    Limits of indeterminant form.-20110106320.jpgPlease help with questions 3 and 6.
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    Last edited by mr fantastic; January 9th 2011 at 10:09 PM. Reason: Re-titled.
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  2. January 9th 2011, 10:08 PM #2
    mr fantastic
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    Quote Originally Posted by niazk90 View Post
    Click image for larger version.  Name: 20110106320.jpg  Views: 7  Size: 351.0 KB  ID: 20372Please help with questions 3 and 6.
    For Q3 note that \displaystyle \frac{\sqrt{x^2 - x}}{x-9} = \frac{\sqrt{1 - \frac{1}{x}}}{1 - \frac{9}{x}}.


    For Q6 note that by multiplying by \displaystyle \frac{\sqrt{2x+3} + \sqrt{x - 1}}{\sqrt{2x+3} + \sqrt{x - 1}} the expression becomes \displaystyle \frac{x + 4}{\sqrt{2x+3} + \sqrt{x - 1}}.
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