# Math Help - Limits of indeterminant form.

1. ## Limits of indeterminant form.

For Q3 note that $\displaystyle \frac{\sqrt{x^2 - x}}{x-9} = \frac{\sqrt{1 - \frac{1}{x}}}{1 - \frac{9}{x}}$.
For Q6 note that by multiplying by $\displaystyle \frac{\sqrt{2x+3} + \sqrt{x - 1}}{\sqrt{2x+3} + \sqrt{x - 1}}$ the expression becomes $\displaystyle \frac{x + 4}{\sqrt{2x+3} + \sqrt{x - 1}}$.