function of area of isosceles triangle
The equal sides of an isosceles triangle are 2. If x is the base, express the area as a function of x.
The area of a triangle is 1/2 BH and the height of an Isosceles triangle I learned is :
H=square root of b^2-1/4a^2 (b is base, a is either of the equal sides)
So I got as an answer :
A = 1/2 X (x^2-1/4(2)^2)
Im pretty sure this is wrong. I keep trying to check it but Im getting it wrong. The official answer is:
A = 1/4X SQRT of 16-x^2
Dont see how to get that answer, can someone please help?