Im pretty sure I was wrong thinking that. SO I dont really get what to do. (other then just make up any equation that when you put x+1 threw would equal the same as f(x+1)).
As for x(a) and x(a+1), I dont know how to answer that without having f(x) to plug them into. I guess you MIGHT mean the constant before x^2 for "a".
I dont really see where to go because im thinking it says find f(u), u = x+1. So thats really saying find f(x+1) isnt it? and isnt f(x+1) the equation that they give me? So thats not really helping me. So im definitly missing something.