The question says to solve sin (z) = cosh (2) by equating the real and imaginary parts.
These are the two equations to solve.
From this, I am just supposed to include when
then
The question says to solve sin (z) = cosh (2) by equating the real and imaginary parts.
These are the two equations to solve.
From this, I am just supposed to include when
then
From Equation 2, you have gotten two cases, OR .
Case 1: .
Substitute into Equation 1 to give
.
But since for all , that means we can only accept even values of , and therefore, that restricts to be .
When that is the case, .
So the first solution is .
Case 2: .
Substitute into Equation 1 to give
according to Mathematica.
So the second solution is .