Given that x2 + y2 = 11xy
Show that log [ (x-y)/3 ] = 0.5 (logx +logy)
Give that log [ (x-y)/3 ] = 0.5 (logx +logy)
Show that x2 + y2 = 11xy
I really liked the log unit and understood it, but I was stumped on this question. It was for a test and it keeps bothering me.
What I did was completely wrong, but I will be able to understand it if someone shows the solution.