Given log(2) = .3 and log(3) = .47, what is log(5)?
Thank You
Hello, nertil1!
You solved it . . . Good for you!
$\displaystyle \text{Given: }\:\log(2) = 0.3\,\text{ and }\,\log(3) = 0.47\text{, find }\log(5)$
Did you solve it like this?
$\displaystyle \log(5) \;=\;\log\left(\dfrac{10}{5}\right) \;=\;\log(10) - \log(2) \;=\;1 - 0.3 \;=\; 0.7$