Thread: solving equation

Hi, can anyone help me with this:

y^2=2x+3
x^2+y^2=4

I tried substituting the first line in the second one :

x^2+2x+3=4 => x^2+2x+3-4 = 0 => x^2+2x-1=0

And solve it as a quadratic equation, where x = -1+-sqrt(2)

Am i missing something because, the rezult is not so convinsing.

Thanks a lot. I appreciate it.

Your answer (at least for x) is correct. The more you practice these problems (including those whose answers are not "nice" numbers like integers), the more you'll become comfortable with them.