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About LinkBacksCan anyone help with this rational inequality
7/(x+1)>7
I think its zero but apparently the real answer is -1<x>0.
The first thing we all want to do is multiply both sides of the inequality by (x+1), but we need to be careful because the inequality changes if we multiply by a negative value, so 2 cases:
Case 1) x+1 < 0 or x < -1
Then 7 < 7(x + 1) and 7 < 7x + 7 and we get x > 0
so taking all the conditions, we have x < -1 and x > 0, but this is not possible, so case 1 gives no solutions
Case 2) x + 1 > 0 or x > -1
Then 7 > 7(x+1) and 7 > 7x + 7 and we get x < 0
so taking all the conditions we have x > -1 and x < 0, this is a range and can be written as -1 < x < 0
[soze=3]Hello, homeylova223![/size]
. WHAT is zero?
We have: .
Divide by 7: .
Then we have: .
Multiply by -1: .
If a fraction is negative: the numerator and denominator have opposite signs.
. . . This says: .and
. . . impossible
. . . This says: .and
This is possible: .
Hello, homeylova223!
We have: .
Divide by 7: .
Then we have: .
Multiply by -1: .
If a fraction is negative: the numerator and denominator have opposite signs.
. . . This says: .
. . . This says: .
This is possible: .
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Originally Posted by homeylova223 
