If you know sin(z)
Why not just expand z^2 into real and imaginary parts, then it looks just like z' = (x^2 - y^2) + (2xy)i.
Can you find sin(z^2) = sin(z') now?
I need help rewriting f(z) as f(z)=u+iv. In particular I need help with sin(z^2) and sec(z).
I believe Sec(z) would just be Sec(x)Sech(y)+i(-Csc(x)Csch(y)). Or just the inverse of cos(z)
However I cannot find a way to relate Sin(z) to Sin(z^2).
Thank You in advance.