Hi, My problem is this : find the equation of the circle determined by the given conditions :
center (-2,3) and tangent to the line 4y-3x+2=0.
the equation for the line is y=3/4x -1/2 (im pretty sure)
so I drew that line, then I figured I would need to use the distance formula from where the line starting at (-2,3) with slope -4/3 (negative reciprical of 3/4) intersects 4y-3x+2=0.
However, it doesnt intersect at a point, its an arbitrary point. I cant determine the exact x,y of it by graphing. I dont see how to make the distance formula = to an arbitrary point. Also the only other thing I can think of is that the circle can only intersect 4y-3x+2=0 once not twice. I also cant figure out how to make any triangles that would help me. Im stumped. What Do I do? Who knows the answer? I want to know badly.