1/4log˅br + 2log˅bs -2/3log˅bt i multipled the first two terms and divided the last one from the to get an answer of log˅b r^1/4s^2/t^2 is this the correct approach and answer? many thanks.
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Originally Posted by SilvaNoctix 1/4log˅br + 2log˅bs -2/3log˅bt i multipled the first two terms and divided the last one from the to get an answer of log˅b r^1/4s^2/t^2 is this the correct approach and answer? many thanks. Dear SilvaNoctix, Do you mean, $\displaystyle \displaystyle\log_{b}\left(\frac{r^{\frac{1}{4}}s^ 2}{t^{\frac{2}{3}}}\right)$ ??
yes, sorry, i'm not used to writing equations on this site yet. That's exactly what i meant though... is it the correct answer?
Originally Posted by SilvaNoctix yes, sorry, i'm not used to writing equations on this site yet. That's exactly what i meant though... is it the correct answer? Yes it is correct. If you have used the logarithm rules, $\displaystyle \log (A\timesB)=\log A+\log B$ $\displaystyle \log \left(\frac{A}{B}\right)=\log A-\log B$ $\displaystyle \log A^{n}=n\log A$ .....then the approach is also correct.
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