Logs: What is b/a?

**TN17** · December 9th 2010, 07:06 PM

This isn't a homework question. I just want to know how to do this out of curiosity. It looks like something my teacher would put on a quiz, lol.
http://img228.imageshack.us/img228/1799/untitled8av.png

**pickslides** · December 9th 2010, 07:26 PM

You need to find $\displaystyle\frac{b}{a}$ such that $\displaystyle\log_9a = \log_{12}b = \log_{16}(a+b)$

Now looking at the first part of the equation $\displaystyle\log_9a = \log_{12}b$

For these to be equal $\displaystyle a = 1$ and $b = 1$ , are there any other values that work?

but does this hold for the third part of the equation?

**TN17** · December 10th 2010, 01:37 AM

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