This isn't a homework question. I just want to know how to do this out of curiosity. It looks like something my teacher would put on a quiz, lol.
http://img228.imageshack.us/img228/1799/untitled8av.png
This isn't a homework question. I just want to know how to do this out of curiosity. It looks like something my teacher would put on a quiz, lol.
http://img228.imageshack.us/img228/1799/untitled8av.png
You need to find $\displaystyle \displaystyle\frac{b}{a}$ such that $\displaystyle \displaystyle\log_9a = \log_{12}b = \log_{16}(a+b)$
Now looking at the first part of the equation $\displaystyle \displaystyle\log_9a = \log_{12}b $
For these to be equal $\displaystyle \displaystyle a = 1 $ and $\displaystyle b = 1$ , are there any other values that work?
but does this hold for the third part of the equation?