Hi, Can you please help with a question in my homework: The equation x²=k(2x-3) has equal roots. Find the value(s) of k. Don't really have a clue what to do Thanks in advance!
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Rearrange in the form: $\displaystyle ax^2 + bx + c = 0$ Then, since the equation has equal roots, you have: $\displaystyle b^2 - 4ac = 0$ Solve for k
Unknown008, that helped. It's easier than I thought! Thanks!
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