The equation x²=k(2x-3) has equal roots.
Find the value(s) of k.

Don't really have a clue what to do

2. Rearrange in the form:

$ax^2 + bx + c = 0$

Then, since the equation has equal roots, you have:

$b^2 - 4ac = 0$

Solve for k

3. Unknown008, that helped. It's easier than I thought!

Thanks!