Thread: How to isolate "R" (from a log equation)

1. How to isolate "R" (from a log equation)

2. A pretty good attempt, well done!

I prefer not to introduce the $\displaystyle \displaystyle \log$

$\displaystyle \displaystyle 25000 = 10000\left(1+\frac{R}{100}\right)^6$

$\displaystyle \displaystyle 2.5 =\left(1+\frac{R}{100}\right)^6$

$\displaystyle \displaystyle \sqrt[6]{2.5} =1+\frac{R}{100}$

$\displaystyle \displaystyle\sqrt[6]{2.5}-1 =\frac{R}{100}$

$\displaystyle \displaystyle 100(\sqrt[6]{2.5}-1) =R$

3. Thanks.
Ah, okay.
How would I do b), though?
I tried the same method, but I didn't get 360.5%
Would I still use 25 000 and 10000, or is that only for the first 6 years?

4. $\displaystyle \displaystyle 25000 = 10000\left(1+\frac{R}{100}\right)^{0.6}$

$\displaystyle \displaystyle 2.5 =\left(1+\frac{R}{100}\right)^{0.6}$

$\displaystyle \displaystyle (2.5)^{\frac{5}{3}} =1+\frac{R}{100}$

$\displaystyle \displaystyle (2.5)^{\frac{5}{3}}-1 =\frac{R}{100}$

$\displaystyle \displaystyle 100[(2.5)^{\frac{5}{3}}-1] =R$

5. Thank you.
I know where I went wrong now.