obtain the number of terms in the following geometric progression 81, 27 , 9 , 1/243 can i find the number of terms using this the answer that i get is a fraction though and that couldnt be possibly correct
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I suppose there are some skipped terms between 9 and 1/243. So and . The equation is . From here, , or , so n = 10.
Hello, sigma1! . . . . This geometric progression has: . So we have: . We want: . . . Therefore, there are ten terms in the progression.
Originally Posted by emakarov I suppose there are some skipped terms between 9 and 1/243. So and . The equation is . From here, , or , so n = 10. thanks alot.. i see where i went wrong.. if you were suposed to find the sum of the series though would you use this formula
Originally Posted by sigma1 if you were suposed to find the sum of the series though would you use this formula Yes.
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