Finding horizontal asymptote.

• Dec 5th 2010, 01:36 PM
balletgirl
Finding horizontal asymptote.
How do you find the horizontal asymptote of:

13x/(x+18)

I believe the vertical asymptote is -18, because -18 + 18 = 0
• Dec 5th 2010, 01:40 PM
Jerry99
since the degree is the same with the numerator and denominator, you divide the leading coefficients. 13/1 = 13
• Dec 5th 2010, 02:25 PM
pickslides
$\frac{13x}{x+18} = 13-\frac{234}{x+18}$
• Dec 6th 2010, 04:08 AM
HallsofIvy
By the way, the vertical asymptote is the vertical line y= -18, not just the number "-18".