For what values a and b is the complex number z = a + bi a solution to z=z^2 ?
I tried this in many different ways and il post one of my solutions but i dont know if its correct.
(a+bi) = (a+bi)^2
dividing by a+bi on both sides.
1 = a + bi
This tells me that Z is real and that a = 1 and b = 0.
Is this correct?