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Math Help - Am I on the right track.

  1. #1
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    Am I on the right track.

    Ln function
    Solve for x

    x=2.6e^(.1.2) + 1.8e^(2.9)

    do I divide the 2.6 and 1.8 bring to the other side, so I can bring the exponents infront of the e??

    I am not quite sure on this one. Any help would be great, thanks.
    Joanne
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  2. #2
    Member mathemagister's Avatar
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    It seems like you already have the answer to solve for x. You already have x as a constant number. What do you want to solve?
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  3. #3
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    I have to solve for x and have to use the Ln function to get it.
    I am a bit lost on this.
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  4. #4
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    I got it I think I got confused on something. My teacher does not explain well enough, so my notes reflect that.
    I got an answer of 33.497 for x
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  5. #5
    Member mathemagister's Avatar
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    If you meant (-1.2) instead of (.1.2), you're right!
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  6. #6
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    Yes it was -1.2 THANKS ALOT for the help. Really appreciate it. Makes things clearer.
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