Works for me.
Find the equation of the parabola (in standard form) whose vertex is at the origin, has a vertical axis, and passes through the point (-2,5). Thanks
If the origin is zero then y = a(x-0)^2 + 0
y = ax^2
sub in the point (-2, 5) and solve for a
5 = a(-2)^2
5 = a(4)
a = 5/4
Final equation is y = (5/4)x^2