Find the equation of the parabola (in standard form) whose vertex is at the origin, has a vertical axis, and passes through the point (-2,5). Thanks

If the origin is zero then y = a(x-0)^2 + 0

y = ax^2

sub in the point (-2, 5) and solve for a

5 = a(-2)^2

5 = a(4)

a = 5/4

Final equation is y = (5/4)x^2