I got Point P(9,-1) , M(slope)=Fraction 2/3
when i get to do -1=(fraction)2/3(9) I don't know what to do help!!.
The slope-intercept form for a line is:
$\displaystyle y=mx+b, \text{ where } m$ is the slope and $\displaystyle b$ is the y-intercept.
You have a point, P, with x & y values and you also have the slope. Plug these in to find what b is.
$\displaystyle -1=\frac23(9)+b$. (You were very close to this.) Now solve for b and put that back into:
$\displaystyle y=\frac23(x)+b$. (b is the number you just found, of course!)
I have no idea what you are doing or why you are doing it.
as SammyS stated ...
$\displaystyle y = mx + b$
substitute in the given x and y values , and the given slope, then solve for b.
$\displaystyle -1 = \frac{2}{3}(9) + b$
$\displaystyle -1 = 6 + b$
subtract 6 from both sides of the equation ...
$\displaystyle b = -7$
so ... the linear equation that passes throught the point $\displaystyle (9,-1)$ with slope $\displaystyle m = \frac{2}{3}$ is $\displaystyle y = \frac{2}{3} x - 7$
Your work is flawed vaironxxrd.
In the image you gave, this is your work:
$\displaystyle \frac{2}{3}*9=\frac{18}{27}\div\frac{3}{3}=\frac{2 }{3}$
This is incorrect. Actually, we have:
$\displaystyle \frac{2}{3}*\frac{9}{1}=\frac{18}{3}=6$
note that $\displaystyle \frac{9}{1}=9$
As the others have been saying now we use the slope intercept form: $\displaystyle y=mx+b$
Where x and y are the x and y coordinates of a point, m is the slope, and b is the y-intercept.
You have one point: (9,-1) and the slope as 2/3, so we will use this:
$\displaystyle -1=\frac{2}{3}*9+b$ This step is where your error was.
$\displaystyle -1=6+b$
$\displaystyle b=-7$
Now we put this into y-intercept form:
$\displaystyle y=\frac{2}{3}x-7$