The slope of the tangent line:
is the slope and is the y-intercept.
You have a point, P, with x & y values and you also have the slope. Plug these in to find what b is.
. (You were very close to this.) Now solve for b and put that back into:
. (b is the number you just found, of course!)
as SammyS stated ...
substitute in the given x and y values , and the given slope, then solve for b.
subtract 6 from both sides of the equation ...
so ... the linear equation that passes throught the point with slope is
Your work is flawed vaironxxrd.
In the image you gave, this is your work:
This is incorrect. Actually, we have:
As the others have been saying now we use the slope intercept form:
Where x and y are the x and y coordinates of a point, m is the slope, and b is the y-intercept.
You have one point: (9,-1) and the slope as 2/3, so we will use this:
This step is where your error was.
Now we put this into y-intercept form: