ABC has the following co-ordinates: A(3,7)B(-1,-6) and C(-5,3). Determine the equation of the median from vertex C.

This question is giving me a bit of trouble. If someone could please help me out i would greatly appreciate it.

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- January 16th 2006, 05:28 PMScott9909Determine the equation of the median from vertex
ABC has the following co-ordinates: A(3,7)B(-1,-6) and C(-5,3). Determine the equation of the median from vertex C.

This question is giving me a bit of trouble. If someone could please help me out i would greatly appreciate it. - January 16th 2006, 07:32 PMThePerfectHackerQuote:

Originally Posted by**Scott9909**

**Part the First, find the coordinates of midpoint:**By definition, the median from vertex is a line which joins the midpoint of side . But by the midpoint formula the midpoint of is . Thus, the median passes through points and .

**Part the Second, find the equation of median:**Using the slope-point formula which states that the equation of a line passing through point having slope is . Thus, the slope of is . Thus, the equation of line is (use any point for )

Open and simplify,

Q.E.D. - January 16th 2006, 07:56 PMScott9909
Im a bit confused on part 2.

Do you have to find the slope of the line? Im not furmilur with the formula you put up. Ive been taught to do it Y=X2-X1/Y2-y1

and i dont seem to be getting the same slope. - January 16th 2006, 08:09 PMThePerfectHacker
That is exactly what I did . You mean the formula for the equation of the line?

- January 16th 2006, 08:13 PMScott9909
Im not exactly sure. I really dont understand math that well.

are you supposed to do y2-y/x2-x1 with your midpoint and C(-5,3)?

And also if it is what is considered y2 and x2? C or the midpoint.

Sorry if these questions are stupid. - February 18th 2006, 02:43 AMearbothQuote:

Originally Posted by**Scott9909**

you've got the answer to your problem already. I'll give you only a few additional informations:

1. If you have 2 points with the coordinates then you'll get the midpoint

2. A line through 2 points is described completely by the following equation:

Solve this equation for y and you'll get: where is the slope of the line.

I hope that these additional remarks helped a little bit.

Greetings

EB