Results 1 to 2 of 2

Math Help - Find the point(s) of intersection.

  1. #1
    Newbie
    Joined
    Nov 2010
    Posts
    4

    Find the point(s) of intersection.

    Algebra II.

    Find the point(s) of intersection. List all of the solutions.

    The line:
    x -2y = 0

    &

    The circle:
    (x-2)^2 + (y+2)^2 = 36



    For the circle I think the radius is 6 and the center is (2,-2). From there I know that x = 2y but I get lost when substituting it in.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member Educated's Avatar
    Joined
    Aug 2010
    From
    New Zealand
    Posts
    433
    Thanks
    12
    (x-2)^2 + (y+2)^2 = 36

    x = 2y

    Substitute in 2y everytime x appears in the circle equation:

    (2y-2)^2 + (y+2)^2 = 36

    [4y^2 - 8y + 4] + [y^2 + 4y + 4] = 36

    5y^2 - 4y - 28 = 0

    Now use the quadratic formula to solve for y. You should get 2 answers. Substitute in y back into either equation to get the x co-ordinate and these are your points of intersection.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. find the point of intersection of...
    Posted in the Calculus Forum
    Replies: 7
    Last Post: October 7th 2011, 08:06 AM
  2. Replies: 2
    Last Post: October 2nd 2010, 02:22 AM
  3. Replies: 5
    Last Post: July 19th 2010, 12:41 PM
  4. Find point of intersection
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 5th 2009, 09:19 AM
  5. Find cordinates of the point of intersection.
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: August 28th 2008, 10:20 AM

Search Tags


/mathhelpforum @mathhelpforum