Finding Domain and Range of function

**rcs** · Nov 27th 2010, 02:46 PM

Please help on reaching this Domain and Range of the function:

5y( x- 1)( x-3 )=2(5x + 3)

its Domain and Range :
D: x ≠ 1 , 3
R: {y|y ≥ -1/5 or y ≥ - 5}

i would like to know how to reach the solution on domain and range . i'm so confused.

**Mondreus** · Nov 27th 2010, 03:21 PM

If you write it on a more familiar form: $y = \frac{2(5x+3)}{5(x-1)(x-3)}$ you'll see that it is undefined for $x=1$ and $x=3$ since the denominator is 0 for those two values.

**rcs** · Nov 27th 2010, 10:55 PM

Thanks Mondreus !

How about showing the Solution before plugging in the values of x which is done by cases.
im a little confused now.

**HallsofIvy** · Nov 28th 2010, 02:17 AM

Do you understand what "domain" and "range" mean?

**rcs** · Nov 28th 2010, 05:03 PM

HallsofIvy i understand domain and range
i wanted to ask for the manipulation or solution how it is being done to reach to the range and domain. thank you

**rcs** · Dec 3rd 2010, 04:45 AM

how is by Cases done? please help

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