Determine without graphing, whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point.
f(x) = 2x2 - 4x

Find the coordinates of the vertex for the parabola defined by the given quadratic function.f(x) = -x2 - 8x - 4

2. Originally Posted by kjonae_0469

Determine without graphing, whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point.
f(x) = 2x2 - 4x
the coefficient of $x^2$ is positive, therefore, this quadratic has a minimum value. It occurs at the vertex.

To find the vertex of a quadratic of the form $f(x) = ax^2 + bx + c$, we use the formula: $x = \frac {-b}{2a}$

Thus the vertex is the point $\left( \frac {-b}{2a}, f \left( \frac {-b}{2a} \right) \right)$

Find the coordinates of the vertex for the parabola defined by the given quadratic function.f(x) = -x2 - 8x - 4
Use the formula i mentioned above

If you have any more problems, say so