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  1. #1
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    math problem

    The price of an item is given by p= 2x squared-100 Find the plynomial that represents the revenue generated from the sale of x items
    is it set up like? p= x(2x squared -100)? i can't write out the little 2 above the 2x so i have to say squared
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by lizard4 View Post
    i can't write out the little 2 above the 2x so i have to say squared
    you can use "^" to represent powers. typing 2x^2 means 2x squared. also, you can learn to use LaTex, it's not that hard, so you can write 2x^2

    i attached a pdf to the end of this post, it is the LaTex tutorial that you can find on this site

    by the way, you are correct, you would multiply the price function by x to get the revenue function (but dont call it p, call it something else, like r, you already have the function p defined as something else, naming the new function using the same variable causes confusion). why do you think that is how we get the desired function?
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  3. #3
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    Quote Originally Posted by lizard4 View Post
    The price of an item is given by p= 2x squared-100 Find the plynomial that represents the revenue generated from the sale of x items
    is it set up like? p= x(2x squared -100)? i can't write out the little 2 above the 2x so i have to say squared
    Revenue equals price times number sold.
    If price is p(x) where x is the number sold then revenue is R(x)=(x)p(x).
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  4. #4
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    [quote=Jhevon;58456] i attached a pdf to the end of this post, it is the LaTex tutorial that you can find on this site

    [quote]

    Thanks for the attached LaTex tutorial. But where can I find the tutorial on MHF?
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  5. #5
    Grand Panjandrum
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    [quote=curvature;58480]
    Quote Originally Posted by Jhevon View Post

    i attached a pdf to the end of this post, it is the LaTex tutorial that you can find on this site

    quote]

    Thanks for the attached latax tutorail. Where can find it on MHF?
    Its here.

    It is the stick post at the top of the Feedback and Anouncements forum.

    RonL
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