Cosine goes from -1 to 1 cos(180)=-1
tan(90)=DNE tan(z)=y/x when the angle is 90 y=1 and x=0; therefore, 1/0 is undefined. tan isn't less than or equal to 90 but simply less than.
The range of tangent is -90<x<90 excluding the end values.
Three functions are defined as follows:
f: x ---> cos x for the domain 0 <= x <= 180
g: x ---> sin x for the domain 0 <= x <= 90
h: x ---> tan x for the domain p <= x <= q
1) find the range of f
Is the answer: It ranges from cos (0) = 1 to cos (180) = -0.9510565163
2) Given that the range of h is the same as the range of g. Find the value of p and q.
Is the answer: p = 0 as tan (0) = 0 and q = not sure??
How in the world did you get that? Actually, I would have to say the whole problem is badly phrased. The function "f:x--->cos x", as opposed to a problem where we are actually dealing with angles measured in degrees, requires that x be in radians. At first I thought that was what you are doing but the cosine of 180 radians is -0.59846, not what you give. Oh wait! Cosine of 180 grads is -0.9510565. But why in the world would your calculator be set to "grads"? (There are 100 grads in a right angle.)
For x between 0 and 90 degrees (which should have been said explicitely) sine is between 0 and 1. Yes, tan(0)= 0. What angle, x, has tan(x)= 1?2) Given that the range of h is the same as the range of g. Find the value of p and q.
Is the answer: p = 0 as tan (0) = 0 and q = not sure??