1. if ,please show why and have the same parity?
2. proof this using a combinatorial argument:
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2. Hint: .
Last edited by TheCoffeeMachine; November 18th 2010 at 02:31 AM.
"2ab" is clearly even so the parity of is the same as the partity of .
And, of course, since and the parity of is the same as the parity of a.
but i want a proof by a combinatorial argument.
Well, you can prove the binomial theorem (which is what TheCoffeeMachine used) with a combinatorial argument.
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