For the parabolay=x^2

I have determined that thefocusis the point (0, 1/4)

I have determined that thedirectrixis the liney= -1/4

Am I correct?

Printable View

- Nov 15th 2010, 02:27 PMMATNTRNGParabola and Directrix and Focus.
For the parabola

*y*=*x*^2

I have determined that the**focus**is the point (0, 1/4)

I have determined that the**directrix**is the line*y*= -1/4

Am I correct? - Nov 16th 2010, 12:19 AMearboth