I would agree that you've found two points on the line. Now what should you do?
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find the equation by using the two points:
What is that the equation of? The line? You already have that. What does the equation of a plane look like?
ok, let me start again i have the three points (6,6,-1) (13,10,-2) (1,3,2)
find the cross product
sub points (1,3,2)
this is incorrect, however shouldn't it be still correct even if the points are different
Name the three points: 6,6,-1),~Q13,10,-2),~\&~R1,2,3)" alt="P6,6,-1),~Q13,10,-2),~\&~R1,2,3)" />.
Now find the normal: .
Then write the equation of the plane determined by the three points:
BTW: [tex]\times [/tex] gives in LaTeX.
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