I need serious help.
I need to find the Y intercept of the graph
$\displaystyle y= -0.02(x^3 - 38x^2 + 441x - 1620)$
I also need to X when y=3
I also need to find the equation of the inclined path if it hasa gradient of 4/5
Please help
I need serious help.
I need to find the Y intercept of the graph
$\displaystyle y= -0.02(x^3 - 38x^2 + 441x - 1620)$
I also need to X when y=3
I also need to find the equation of the inclined path if it hasa gradient of 4/5
Please help
$\displaystyle y= -0.02(x^3 - 38x^2 + 441x - 1620)$
when $\displaystyle y = 3$ we have
$\displaystyle 3= -0.02(x^3 - 38x^2 + 441x - 1620)$
$\displaystyle \Rightarrow x^3 - 38x^2 + 441x - 1470 = 0$
Trying the factors of 1470, we realize that x = 14 is a root, so (x - 14) is a factor. Dividing the cubic by (x - 14) using long division, we obtain:
$\displaystyle x^3 - 38x^2 + 441x - 1470 = (x - 14) \left( x^2 - 24 x + 105 \right) = 0$
$\displaystyle \Rightarrow x - 14 = 0 \mbox { or } x^2 - 24x + 105 = 0$
$\displaystyle \Rightarrow x = 14 \mbox { or } x = \frac {24 \pm \sqrt {156}}{2}$
when you say inclined path you mean tangent line right?