G(x)=3/x,x>0

Find g^35. How do i solve it? I know for example g^2 is x becus the working is 3/(3/x).

But in this case the power is 35..

Just try a few times of g^2, g^3 and so on to check on the pattern

g^1 = 3/x

g^2 = 3/(3/x) = x

g^3 = g(g^2) = 3/x

g^4 = g(g^3) = 3/(3/x) = x

So g^(positive even) = x, and g^(positive odd) = 3/x

so g^35 = g^(positive odd) = 3/x