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Math Help - problem in ( derivaives )

  1. #1
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    problem in ( derivaives )

    Hi all

    I hope every one is ok ....

    A ) The velocity of this 4 particles at any time t ,its accleration at any time is .

    1 ) 1/secx
    2)2/cosx
    3) 1/tanx
    4)1/sec2x

    my answer is :
    1) 1/cosx
    2)2/-sinx
    3)1/sex2x
    4)1/cos2x

    ----------------------

    B) suppose that u is a differntiable function of x and that u(2) = 2 ud(2) =3
    the derivaives of (2 + u ) respect with x . at x = 2 is ......(4)........


    c) suppose that u is a differntiable function of x and that u(2) = 2 ud(2) =3
    the derivaives of (2 + u ) respect with x . at x = 3 is ......(5)........

    I want your help .
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  2. #2
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    Quote Originally Posted by r-soy View Post
    Hi all

    I hope every one is ok ....

    A ) The velocity of this 4 particles at any time t ,its accleration at any time is .

    1 ) 1/secx
    1/sec(x)= cos(x). What is the second derivative of cos(x)?

    2)2/cosx
    Either write 2/cos(x)= 2sec(x) or "remember" the derivative of cos(x) or use the quotient rule: [tex]\frac{0(cos(x))- 2(-sin(x))}{cos^2(x)}= 2\frac{sin(x)}{cos(x)}\frac{1}{cos(x)}= 2tan(x)sec(x)

    3) 1/tanx
    1/tan(x)= cot(x)= cos(x)/sin(x). Either "remember" the derivative of cot(x) or use the quotient rule: \frac{(-sin(x))sin(x)- cos(x))cos(x)}{sin^2(x)}-\frac{sin^2(x)+ cos^2(x)}{sin^2(x)}= -\frac{1}{sin^2(x)}= -cosec^2(x)

    4)1/sec2x
    sec(x)= 1/cos(x) so 1/sec(2x)= cos(2x). Its derivative, by the chain rule, is -2sin(2x)

    my answer is :
    1) 1/cosx
    2)2/-sinx
    3)1/sex2x
    4)1/cos2x[/quote]
    Every one of these is wrong. You need more practice! And remember that the derivative of f(x)/g(x) is NOT f'(x)/g'(x)! It is \frac{f'(x)g(x)- f(x)g'(x)}{g^2(x)}

    ----------------------

    B) suppose that u is a differntiable function of x and that u(2) = 2 ud(2) =3
    the derivaives of (2 + u ) respect with x . at x = 2 is ......(4)........
    By "ud(2)" do you mean the derivative of u at x= 2, u'(2)= 3?
    You should have learned long ago that the derivative of f(x)+ g(x) is f'(x)+ g'(x) and that the derivative of a constant is 0: (2+ u)'= u' and since u'(2)= 3, the derivative of 2+ u at x= 2 is also 3.


    [quote]c) suppose that u is a differntiable function of x and that u(2) = 2 ud(2) =3
    the derivaives of (2 + u ) respect with x . at x = 3 is ......(5)........
    Once again, the derivative of 2+ u is just the derivative of u since the derivative of the constant, 2, is 0. Since you do not know the derivative of u at x= 3 you cannot say anything about the derivative of 2+ u at x= 3. Are you sure you have copied these problems correctly?

    I want your help .
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