Prove that a polynomial P(x)X^4-3x^2+1 has exactly four radical.
how can i do it?
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I'm not sure if that's the correct way to go about it, but my 2 cents:
Using the quadratic formula, we get:
Then, taking the square root;
Since all the roots in there are real, (the square root of 5 is less that 3) there must be 4 real roots.
so what is the 4 real roots>?
Unknown008 exhibited them in post # 2. Just take ++, +-, -+, -- combinations of the signs, and you'll get all four roots.
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