Prove that a polynomial P(x)X^4-3x^2+1 has exactly four radical. how can i do it? thanks.
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I'm not sure if that's the correct way to go about it, but my 2 cents: Using the quadratic formula, we get: Then, taking the square root; Since all the roots in there are real, (the square root of 5 is less that 3) there must be 4 real roots.
so what is the 4 real roots>?
Unknown008 exhibited them in post # 2. Just take ++, +-, -+, -- combinations of the signs, and you'll get all four roots.
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