f(x) = 8/x-9 and g(x) = 14/(x+3)

all i know is that x cannot equal 9 and -3.

what is the domain of f+g and f/g in interval notation??

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- Nov 2nd 2010, 08:35 PMvecomaDomain of a function?!
f(x) = 8/x-9 and g(x) = 14/(x+3)

all i know is that x cannot equal 9 and -3.

what is the domain of f+g and f/g in interval notation?? - Nov 3rd 2010, 08:01 AMHallsofIvy
"f+ g" is defined by "f+ g(x)= f(x)+ g(x)". In order that f+ g (x) exist, f(x) and g(x) must both exist (even if adding algebraically appears to eliminate a "division by 0").

That means that the domain of f+ g is the**intersection**of the domains of f and g. The domain of f(x)= 8/(x- 9) (which is NOT what you wrote but must be what you meant since the domain of 8/x- 9 is "all real numbers except**0**") is "all real numbers except 9" and the domain of g(x)= 14/(x+ 3) is "all real numbers except -3". The domain of f+ g is "all real numbers except 9 and -3". In interval notation, that would be .

For f/g, both f and g must exist and g(x) must not be 0. Since 14/(x+ 3) is never 0 (a fraction is equal to 0 if and only if its numerator is 0), the domain of f/g is exactly the same as f+ g.