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Math Help - graph help

  1. #1
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    Smile graph help

    i need help with graphing (f)x = 3x+2
    thank you
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by lizard4 View Post
    i need help with graphing (f)x = 3x+2
    thank you
    f(x) = y = 3x + 2
    This is just a line with slope = 3 and y-intercept = 2

    To draw a line, all we need are two points, the intercepts are always good points to use.

    For x-intercept, set y = 0

    \Rightarrow 0 = 3x + 2

    \Rightarrow x = - \frac {2}{3}

    So our x-intercept is \left( - \frac {2}{3}, 0 \right)

    For y-intercept, we simply have the lone constant as the intercept. So our y-intercept is at y = 2, which is the point (0,2)

    But why is this? Let's see.

    For y-intercept, set x = 0

    \Rightarrow y = 3(0) + 2 = 2

    \Rightarrow y = 2

    So the y-intercept is (0,2)

    Now just plot these points on a graph and draw a straight line through them, as you see below


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