1. ## graphs

Suppose we have a graph of y = xsquared + 3x -2. What lines would you draw on it to solve the following eqautions?

a) xsquared + 3x + 5 = 0
b) xsquared + 4x -4 = 0
c) xsquared -x - 1 = 0

2. a) $x^2 + 3x -2 +7 =0$
$x^2+3x -2 = -7$

$y_{1} = x^2+3x-2$
$y_{2} = -7$

when $y_{1}=y_{2}$
you get the x value that satisfies the equation

try others out in the same manner

3. Hello, Natasha1!

I'll do one of them . . .

Suppose we have a graph of $y \:=\: x^2 + 3x -2.$
What lines would you draw on it to solve the following eqautions?

$b)\;\;x^2 + 4x -4 \:=\: 0$

Draw the line $y \:=\:-x + 2$ . . . . why?

To find the intersections of the parabola and the line,

. . we have: . $x^2+3x-2 \:=\:-x + 2 \quad\Rightarrow\quad x^2 + 4x - 4 \:=\:0$

The $\,x$-coordinates of the intersections are the roots of the quadratic equation.