points of intersection

**rlkmg** · October 25th 2010, 12:25 PM

$y=x^3-2x+1$

$y=x^2$
The question says to use the bisection method to find the points of intersection of the 2 curves. I know how to use the bisection method to find the root of an equation (like on this page First Steps in Numerical Analysis), but how would I use it to find the point of intersection? Thanks.

Moderator edit: Use [tex] and [/tex] tags NOT [latex] and [/latex].

**pickslides** · October 25th 2010, 12:48 PM

You have $y=x^3-2x+1$ and $y=x^2$ and intersection occurs at $x^2=x^3-2x+1$

Holding that thought

$x^2=x^3-2x+1$

$x^2-x^3+2x-1= 0$

Now apply the bisection method, to kick if off try the interval (0,1)

**rlkmg** · October 25th 2010, 12:58 PM

thanks! got the answer

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