
points of intersection
$\displaystyle y=x^32x+1$
$\displaystyle y=x^2$
The question says to use the bisection method to find the points of intersection of the 2 curves. I know how to use the bisection method to find the root of an equation (like on this page First Steps in Numerical Analysis), but how would I use it to find the point of intersection? Thanks.
Moderator edit: Use [tex] and [/tex] tags NOT [latex] and [/latex].

You have $\displaystyle y=x^32x+1$ and $\displaystyle y=x^2$ and intersection occurs at $\displaystyle x^2=x^32x+1$
Holding that thought
$\displaystyle x^2=x^32x+1$
$\displaystyle x^2x^3+2x1= 0$
Now apply the bisection method, to kick if off try the interval (0,1)

thanks! got the answer :)