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Thread: What is the inverse function of...

  1. October 20th 2010, 01:55 PM #1
    katedew987
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    What is the inverse function of...

    ...f(x)= (1 - x)^2 on [-1, 2]?
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  2. October 20th 2010, 02:16 PM #2
    pickslides
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    The inverse of f(x) = y = (1-x)^2 is found as follows


    Swap x and y and solve for y.

    x = (1-y)^2

    \sqrt{x} = 1-y

    \sqrt{x}-1 = -y

    1-\sqrt{x} =y

    y=f^{-1}(x) = 1-\sqrt{x}

    but the inverse only exists for a function that is one to one. Does your interval imply this?
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