f(x) = 1/2 ( (e^(x^3) + e^(-x^3) ) Thankyou
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Well, if you convert to the hyperbolic trigonometric functions, you'd have $\displaystyle \displaystyle f(x)=\frac{1}{2}(e^{x^{3}}+e^{-x^{3}})=\cosh(x^{3}).$
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